Hacker Rank "Designer PDF Viewer" Solution

Problem : -----

When you select a contiguous block of text in a PDF viewer, the selection is highlighted with a blue rectangle. In this PDF viewer, each word is highlighted independently. For example:

In this challenge, you will be given a list of letter heights in the alphabet and a string. Using the letter heights given, determine the area of the rectangle highlight in  assuming all letters are  wide.

For example, the highlighted . Assume the heights of the letters are  and . The tallest letter is  high and there are  letters. The hightlighted area will be  so the answer is .

Function Description

Complete the designerPdfViewer function in the editor below. It should return an integer representing the size of the highlighted area.

designerPdfViewer has the following parameter(s):

• h: an array of integers representing the heights of each letter
• word: a string

Input Format

The first line contains  space-separated integers describing the respective heights of each consecutive lowercase English letter, ascii[a-z]. 
The second line contains a single word, consisting of lowercase English alphabetic letters.

Constraints

• , where  is an English lowercase letter.
•  contains no more than  letters.

Output Format

Print a single integer denoting the area in  of highlighted rectangle when the given word is selected. Do not print units of measure.

Sample Input 0

1 3 1 3 1 4 1 3 2 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5
abc

Sample Output 0

9

Explanation 0

We are highlighting the word abc:

Letter heights are ,  and . The tallest letter, b, is  high. The selection area for this word is .

Note: Recall that the width of each character is .

Sample Input 1

1 3 1 3 1 4 1 3 2 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 7
zaba

Sample Output 1

28

Explanation 1

The tallest letter in  is  at .

Solution : --------

<?php

/* Write your PHP code here */

//Height of each english alphabet.

$h = array(1,3,1,2,4,6,4,3,5,3,7,8,6,5,3,0,0,8,7,5,4,3,7,4,3,7);

//String is given

$word = "abc";

$arr = array();

$a = 0;

$len = 0;

$value = 0;

$ans = 0;

for($i=0;$i<strlen($word);$i++){

$len = ord(strtolower($word[$i]))-97; // a= 1, z= 26, 

$value = $h[$len];

$arr[$i] = $value;

}

rsort($arr);

$a = $arr[0];

$ans = $a * strlen($word);

echo $ans; // Area of the word

?>

Ajayyadavexpo

Thank you